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“showed a trend”

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showed a trendp = 0.11952.4× alpha
In contrast, potassium calcium-activated channel subfamily M alpha 1 ( KCNMA1 ), another gene associated with EDHF-mediated responses, showed a trend toward increased expression in GDM HUVECs compared to NG, both under basal conditions ( p = 0.1195) and after insulin stimulation ( p = 0.0548) ( Figure 6 F), indicating a possible compensatory upregulation of the EDHF pathway in GDM. 3.
showed a trendP = 0.122.4× alpha
However, consistent with our observations after a single injury, SOCS3 MscKO muscles contained a higher proportion of fibers with a single central nucleus after two sequential injuries ( Fig 4I ; ** P < 0.01) compared to muscles from control mice which showed a trend towards a higher proportion of fibers with more than two centralised nuclei ( Fig 4I ; P = 0.12).
showed a trendp = 0.122.4× alpha
Subgroup analyses showed a trend for the reduction in triglycerides in the EG to be larger at longer-term follow-up (i.e., 6–12 months; MD −0.16; 95% CI −0.37 to 0.04; p = 0.12; I 2 = 0%) than at 3 months (MD −0.06; 95% CI −0.27 to 0.15; p = 0.55; I 2 = 0%), but both effects were not significant ( Figure 5 ). 3.4.4.
showed a trendp = .122.4× alpha
When later events were included, both the REMoDL-B and LLMPP data showed similar results (OS HR = 2.11, 95% CI = 1.115–3.993; p = .019 and HR = 2.17, 95% CI = 1.109–4.242; p = .02; supplemental Figure 3 A,B, respectively), while the HMRN cohort showed a trend for reduced survival in the high-risk group, (HR = 1.39, 95% CI = 0.917–2.106; p = .12; supplemental Figure 3 C); and we have reasoned that the performance of the discriminator may reflect the number of non-lymphoma–related deaths in this population-based cohort.
showed a trendp = 0.122.4× alpha
(e) The ratio of open arm to total arm entries in the elevated plus maze showed a trend towards more open arm entries in J20 animals and a recovery of this in GluA2 G/G /J20 mice (Welch’s ANOVA W (3,29.15) = 2.12, p = 0.12; n’s : WT = 15, GluA2 G/G = 13, J20 = 16, GluA2 G/G /J20 = 14).