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“showed a trend”

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showed a trendp = 0.061.2× alpha
amygdala activity Finally a William's test comparing the size of the correlations between ACS and DLPFC reactivity with that between ACS and amygdala activity showed a trend to significance ( t = 1.53, df = 15, p = 0.06) suggesting individual differences in ACS were more strongly correlated with DLPFC than amygdala activity.
Prefrontal control of attention to threat.
Front Hum Neurosci · 2013 · PMC3564011
showed a trendP = .061.2× alpha
Carotenoids were not significantly related to risk of dementia or AD, except for plasma trans‐β‐carotene, which showed a trend to be related to a higher risk of dementia (hazard ratio [HR] per standard deviation [SD]: 1.09; 95% confidence interval [CI]: 1.00, 1.20; P = .06) and α‐carotene, which also trended toward a higher AD risk alone (HR per SD: 1.15; 95% CI: 1.02, 1.29; P = .02).
Plasma antioxidants and risk of dementia in older adults.
Alzheimers Dement (N Y) · 2021 · PMC8418668
showed a trendP = 0.061.2× alpha
In Cox proportional hazards models, high biomarker levels showed a trend toward conferring a higher risk of “not getting off treatment” as compared to low biomarker levels (for Gal‐9, hazard ratio [HR] 0.32, P = 0.06; for TNFRII, HR 0.24, P = 0.08; for CXCL10, HR 0.39, P = 0.1; for Gal‐1, HR 0.41, P = 0.1).
showed a trendp = 0.061.2× alpha
Contingency table analysis did not provide any evidence for an association between IDO gene expression in tumor specimens and three classical clinicopathological parameters, PSA, pT, and Gleason score, while IL-6 gene expression was associated with PSA ( p = 0.02) and showed a trend toward association with Gleason score ( p = 0.06) (Table 5 ).
showed a trendp = 0.061.2× alpha
Results of the AST reveal that Tg mice performed significantly better than Wt mice on the compound discrimination reversal (CDR) phase (p = 0.01) ( Figure 6 A); they also showed a trend for improved performance on the simple discrimination (SD) phase (p = 0.06) and on the intradimensional reversal (IDR) phase (p = 0.08) ( Figure 6 A).